# Gradient checking quiz

April 15, 2014 1 Comment

Let . Furthermore, let and . You use the formula

to approximate the derivative. What value do you get using this approximation ?(When ,the true, exact derivative is

).

The Octave code that I used to solve this is

((1+0.01)^3-(1-0.01)^3)/(2*0.10)

**3.0001**

(2*0.10) it should be 2*0.01